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4 years ago

Passes through(4,7)Slope=2

Mathematics

1 answer:

Anna71 [15]4 years ago

7 0

Answer:

Step-by-step explanation:

Slope = 2 and passes point (4,7)

The equation is y - y1 = m(x - x1)

And y1 = 7 while x1 = 4, m = 2

: - y - 7 = 2(x - 4)

y - 7 = 2x - 8

y = 2x - 8 + 7

y = 2x - 1 this is the equation

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How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y

son4ous [18]

Solution:

Given:

$x^2=6y$

Part A:

The vertex of an up-down facing parabola of the form;

$\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}$

Rewriting the equation given;

$\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\ \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\ \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\ \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\ \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}$

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

$\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}$

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

$\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}$

Therefore, the focus is;

$(0,\frac{3}{2})$

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

$\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}$

Therefore, the directrix is;

$y=-\frac{3}{2}$

3 0

1 year ago

In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de

Svetach [21]

Answer:

The 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

Step-by-step explanation:

The information provided is as follows:

$x=507\\n=32601\\\text{Confidence level }=99\%$

The sample proportion is:

$\hat p=\frac{x}{n}=\frac{507}{32601}=0.016$

The critical value of z for 99% confidence level is, z = 2.56.

Compute the 99% confidence interval for the proportion of ASD in Arizona as follows:

$CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.016\pm 2.58\cdot\sqrt{\frac{0.016(1-0.016)}{32601}}\\\\=0.016\pm 0.0018\\\\=(0.0142, 0.0178)\\\\\approx (0.014, 0.018)$

Thus, the 99% confidence interval for the proportion of ASD in Arizona is (0.014, 0.018).

6 0

3 years ago

Factor the following quadratic expression. 2p2−19p+35 I don't get this

jek_recluse [69]

Answer:

(p - 7)(2p - 5)

Step-by-step explanation:

$2 {p}^{2} - 19p + 35 \\ \\ = 2 {p}^{2} - 14p - 5p + 35 \\ \\ = 2p(p - 7) - 5(p - 7) \\ \\ = (p - 7)(2p - 5)$

5 0

3 years ago

Plz help. 20 points!!

saw5 [17]

(1) Addition property
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3 years ago

Identify the property used in this equation: (–2) + 6 + 1 = 1 + 6 + (–2)

ruslelena [56]

(-2) + 6 + 1 = 1 + 6 + (-2)
-2 + 7 = 7 - 2
5 = 5

7 0

4 years ago