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murzikaleks [220]
3 years ago
13

Write a quadratic equation with integer coefficients and the given numbers as solutions.

Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:

1.)  f(x) = x*x - 7x + 10

2.) f(x) = x*x - 5x

3.) f(x) = 4*x*x - 5x - 6

4.) f(x) = 6*x*x -5x + 1

Step-by-step explanation:

1.)  2 and 5     (x -2)(x - 5) = f(x)  =  x*x - 7x + 10

2.)  0 and 5     f(x) = x*(x -5) =  x*x - 5x

3.) -3/4  and 2     (x + 3/4)(x -2) = x*x - (5/4) x - 3/2,

 need integers   f(x) = 4xx - 5x - 6

4.) 1/2  and 1/3    (x - 1/2)(x - 1/3) = f(x)

 x*x  - 1/3 x  - 1/2 x +  1/6  

xx  -  5/6  x  + 1/6

6 xx - 5x  + 1

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Step-by-step explanation:

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Is 0.11 * 10-6 in scientific notation? If not, explain.
Nonamiya [84]

Answer:

No, it is not in scientific notation. The first factor is not greater than or equal to 1.​

Step-by-step explanation:

Scientific notation is a method of writing numbers as the product of two factors where the first factor is a number whose absolute value is greater than or equal to 1 but less than 10.

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3 years ago
Read 2 more answers
2. Next she needs to find her maximum heart rate m by subtracting her age a from 220. Write an
Travka [436]

Answer:

220 - a = m

Step-by-step explanation:

a is her age

7 0
3 years ago
From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
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