(x + 4) (x - 3)
a = 4
b = -3
a^2 + b^2 = ...
= 4^2 + (-3)^2
= 16 + 9
= 25
A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
yez they can but it depend on wat type of triangle
D. works because if you work it out that means 2n=140 and then divide by 2 which means n=70 and the other number is 71
Answer:
You will put 1220.83ft³ of water in the pool
Step-by-step explanation:
First of all we have to calculate the volume of the pool and then calculate 80% of that volume
radius = half of diameter
d = 18ft
r = 18ft / 2 = 9ft
To calculate the volume of a cylinder we have to use the following formula:
v = volume
h = height = 6ft
π = 3.14
r = radius = 9ft
v = (π * r²) * h
we replace with the known values
v = (3.14 * (9ft)²) * 6ft
v = (3.14 * 81ft²) * 6ft
v = 254.34ft² * 6ft
v = 1526.04ft³
The volume of the cylinder is 1526.04ft³
If it is filled to 80% then we have to multiply the volume by 80/100
1526.04ft³ * 80/100 = 1220.83ft³
You will put 1220.83ft³ of water in the pool
