Answer:
C. –x + 8y = 56
Step-by-step explanation:
Write in standard form.
x − 8
y = −
56
This is a linear function in the slope - intercept form:
y = m x + b and we need a standard form:
a x + b y = c
y = 1/8 x + 7 / * 8 ( we will multiply both sides of equation by 8 )
8 y = x + 56
- x + 8 y = 56 / * ( - 1 )
x - 8 y = - 56
The equation is y = 1/8x + 7
Standard form equation is Ax + By = C, where A > = 0.
First eliminate the fractions by multiplying the equation by 8
8y = x + 56
Subtract x from each side
-x + 8y = 56
SInce x coeficient can't be negative multiply the equation by negative one.
x - 8y = -56
<u>Step-by-step explanation:</u>
(a) A natural number that is greater than 25 and less than 40
Natural Number : These are numbers starting from 1 or also sometimes from zero and are all positive ! A natural greater than 25 & less than 40 is 30 .
(b) An integer which is less than -5 and a multiple of 2
Integer : An integer is a whole number not a fraction including 0 . It can be positive or negative ! Integer less than -5 and a multiple of 2 is -6.
(c) A rational number between 1 and 2
Rational Number : A number which can be expressed in form of p/q where q is not equal to 0 . A rational number between 1 & 2 is 3/2 .
(d) An irrational number between 8 and 9.
Irrational Number: A real number which is not rational or can't be written in form of p/q . An irrational number between 8 & 9 is 
.
6y + 12 = 3y - 3
Subtract 3y on both sides
3y + 12 = -3
Subtract 12 on both sides
3y = -15
Divide by 3 on both sides
y = -5
Two thousand nine hundred twenty-nine and eight hundred seventy-four thousandths
Answer:
El espesor de un chip es de 0.12mm
Y el diámetro de un átomo de cobre, mide aprox:
0.00000000133 m
Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm
Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm
Primero, escribamos ambos valores en las mismas unidades, sabiendo que:
1m = 1000mm
Podemos reescribir:
0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm
Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm
Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:
N = (0.12mm)/(0.00000133mm) = 90,225.6
Redondeamos al próximo número entero:
N = 90,226
Esa es la cantidad de átomos que se necesitan.
