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OLEGan [10]
3 years ago
14

Identify the maximum, minimum, and amplitude from the graph shown.

Mathematics
2 answers:
boyakko [2]3 years ago
5 0

Answer:

Minimum: -4

Maximum: 4

Amplitude: 4

Step-by-step explanation:

These are the answers on edg... hope this helps!

rewona [7]3 years ago
3 0
The maximum value of the function can be observed when x = pi. In this case the maximum value is y = 4.
 The minimum value of the function can be observed when x = 0 or when x = 2pi. In this case the minimum value is y = -4.
 The peak-to-peak amplitude of the function is A = 8.
 The zero-peak amplitude of the function is A = 4.
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Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩
klemol [59]

\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle


\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt


\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle


\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1

\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2

\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3


With the initial condition \mathbf r(0)=\langle4,6,3\rangle, we find


\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9

\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6

\dfrac92\cdot0^2+C_3=3\implies C_3=3


So the particular solution to the IVP is


\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle

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3 years ago
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HACTEHA [7]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Oliga [24]

Answer:

(2,4)

Step-by-step explanation:

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