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3 years ago

Identify the maximum, minimum, and amplitude from the graph shown.

Mathematics

2 answers:

boyakko [2]3 years ago

5 0

Answer:

Minimum: -4

Maximum: 4

Amplitude: 4

Step-by-step explanation:

These are the answers on edg... hope this helps!

rewona [7]3 years ago

3 0

The maximum value of the function can be observed when x = pi. In this case the maximum value is y = 4.
The minimum value of the function can be observed when x = 0 or when x = 2pi. In this case the minimum value is y = -4.
The peak-to-peak amplitude of the function is A = 8.
The zero-peak amplitude of the function is A = 4.

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The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the

Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

$6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}$

So, a = 5.

Thank you.

7 0

4 years ago

54 divided by 2,263????????

forsale [732]

Answer:

0.02386212991

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Does anybody know how to do this and explain it to me clearly plz and thx <br><br><br> - 1/2 x = 6

Usimov [2.4K]

1) first you multiply each side by -2
1a) that clears the -1/2
x = -12

3 0

4 years ago

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nasty-shy [4]

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7 0

3 years ago

The set for a school play needs a replica of a historic building painted on a backdrop that is 20 feet long and 16 feet high. Th

expeople1 [14]

Answer:

Stage crewmember's calculation is incorrect

Correct = 1/16x 1/16y

Step-by-step explanation:

Given that:

Dimension of backdrop : 20 feets long ; 16 feets high

Actual dimension of building : 320 feets long ; 256 feets high

The correct scale factor can be obtained thus :

Ratio of backdrop dimension to the actual dimension of building

Length : 20 / 320 = 1 /16

Height : 16 / 256 = 1/16

Hence, stage crewmember's calculation of (1/20x ; 1/20y) is incorrect.

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3 years ago