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3 years ago

Identify the maximum, minimum, and amplitude from the graph shown.

Mathematics

2 answers:

boyakko [2]3 years ago

5 0

Answer:

Minimum: -4

Maximum: 4

Amplitude: 4

Step-by-step explanation:

These are the answers on edg... hope this helps!

rewona [7]3 years ago

3 0

The maximum value of the function can be observed when x = pi. In this case the maximum value is y = 4.
The minimum value of the function can be observed when x = 0 or when x = 2pi. In this case the minimum value is y = -4.
The peak-to-peak amplitude of the function is A = 8.
The zero-peak amplitude of the function is A = 4.

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Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

4 0

3 years ago

CAN ANYONE HELP ME ANSWER THIS PLEASE

HACTEHA [7]

Answer: 14/45

Step-by-step explanation: The probability that they first event will occur is 2/10. The probability that the second event will occur is 1/9. If you multiply those like it says in the hint you will get 14/45. (I think this is right)

5 0

3 years ago

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Volgvan

Answer:

-3072

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

-3/5 + ( - 1/10) simplified fraction

34kurt