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valentinak56 [21]
3 years ago
7

A toy American Eskimo dog has a mean weight of 8 pounds with a standard deviation of 1 pound. Assuming the weights of toy Eskimo

dogs are normally distributed, what range of weights would 95% of the dogs have?
a. 7-9 pounds
b. 6-10 pounds
c. 5-11 pounds
d. 4-12 pounds​
Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

Option b) 6-10 lbs

Step-by-step explanation:

Given that X, the weight of  toy American Eskimo dog has mean of 8 pounds with a standard deviation of 1 pound

For 95% of the dogs according to normal distribution would lie between 2 std deviations on either side of the mean.

i.e. lower bound= Mean- 2 std deviation = 8-2 =6

Upper bound = Mean +2 std dev = 8+2 =10

Hence range of weights would be

6-10 lbs

Option b is the answer

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cestrela7 [59]
It is a straight angle because it is on a straight line.

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3 years ago
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Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

3 0
3 years ago
Imagine that you have a very large barrel that contains tens of thousands of M&amp;M's. According to the official M&amp;M websit
Finger [1]

Answer:

(A)20%, 20%, 20%, 20%, 20%

Step-by-step explanation:

We are told that 20% of the M&M's produced by the Mars Corporation are Orange in color. If 5 students take a random sample of 50 M&M's, the most plausible percentage of orange candies that will be obtained is:

20%, 20%, 20%, 20%, 20%

This is as a result of the fact that in research experiments, a sample is a representation of the whole. Any result which holds for a random sample should hold for the total population and vice versa.

5 0
3 years ago
A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than
aleksklad [387]

Answer:

 The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  13

    The sample mean is  \= x =  9.63

     The standard deviation is  s =  0.585

      The significance level is  \alpha  =  0.05

The Null Hypothesis is  H_o :  \mu = 0

The Alternative  Hypothesis  is  H_a =  \mu < 10

The test statistic is  mathematically represented as

          t =  \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }

Substituting values

          t =  \frac{9.63  - 10 }{\frac{0.585}{\sqrt{13} } }

         t =  -  2.280

Now the critical value for \alpha is  

     t_{\alpha } = 1.645

This obtained from the critical value table

  So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

 The conclusion is that the researcher was correct

 

 

6 0
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Ksenya-84 [330]

Answer:

see explanation

Step-by-step explanation:

Given that Bilal is age y and his mother is 25 years older, then

a. Bilal's mothers age is y + 25

b. the sum of their ages = y + y + 25 = 2y + 25

c. Mother is y + 25 = 12 + 25 = 37 years

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