Answer:
5AB + 40 = +2
Step-by-step explanation:
IN FIRST BLANK (5AB)
SECOND BLANK (40)
Answer:
-6
Step-by-step explanation:
f(x) = -x-1
Find f(5), <u><em>this means that anywhere you see </em></u><u><em>x</em></u><u><em>, you substitute in </em></u><u><em>5</em></u><u><em>.</em></u>
f(x) = -x-1
f(5) = -(5)-1
<u>Take note of the signs.</u>
f(5) = -6
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Answer: x = 6
Step-by-step explanation:
Because we are given that the two figures are already similar, we can set up a proportional relationship to determine the value of x. Since the larger rectangle has a width of 21 and the smaller rectangle has a width of 7, those values can be used as the numerators in the proportion. Since the larger rectangle's length is x plus the additional 3 units on the smaller rectangle, x+3 and 3 can be used as the denominators in the proportion.
Next, we set up the proportion as follows:
Then, you cross multiply to get the equation:
After solving down algebraically, you get the value of x to be 6.
I hope this helps!
Answer:
Range is (-8,00)
Step-by-step explanation:
A) There are two possible measurements for the 3rd side. It depends of if you want the 16in piece to be a leg of the hypotenuse. If the 16in side is a leg, then the 3rd side would measure 20.6in. If the 16in side is the hypotenuse, then the 3rd side would measure 9.3in.
b) Either of these triangles could be doubled to make the 2nd triangle. You would have sides of 26in, 32in, and 41.2in. Or you would have sides measuring 18.6in, 26in, and 32in.
c) Because the sides of a right triangle have to satisfy the Pythagorean Theorem adding the same number to all three sides will not create a right triangle. If we are letting the 16in side be a leg
(13+x)²+(16+x)²=(20.6+x)² would have to be true. If you multiply it out and combine terms you find that. 2x²+58x+425=x²+41.2x+425. If we try to solve for x we get x²+16.8x=0. This has two solutions: 0 and -16.8. Neither of those work in this situation because adding zero wouldn't change the triangle and adding the negative would leave you with sides of negative length. You would need up with similar results if you tried it with the other set of numbers.
