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ira [324]
3 years ago
6

Is the binomial a factor of the polynomial nominal function?

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

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M = -4 -4 / 5- 3 = -8/2 = -4

y = -4x + b

4 = -12 + b

b = 16

y = -4x + 16
3 0
3 years ago
48 lbs. equals how many kilograms?
Dahasolnce [82]
Your answer is 21.7724<span>Kilograms</span>
4 0
3 years ago
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VLD [36.1K]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Consider the region bounded by 4y=x^2 and 2y=x.
gayaneshka [121]

Answer:

a) ⅓ units²

b) 4/15 pi units³

c) 2/3 pi units³

Step-by-step explanation:

4y = x²

2y = x

4y = (2y)²

4y = 4y²

4y² - 4y = 0

y(y-1) = 0

y = 0, 1

x = 0, 2

Area

Integrate: x²/4 - x/2

From 0 to 2

(x³/12 - x²/4)

(8/12 - 4/4) - 0

= -⅓

Area = ⅓

Volume:

Squares and then integrate

Integrate: [x²/4]² - [x/2]²

Integrate: x⁴/16 - x²/4

x⁵/80 - x³/12

Limits 0 to 2

(2⁵/80 - 2³/12) - 0

-4/15

Volume = 4/15 pi

About the x-axis

x² = 4y

x² = 4y²

Integrate the difference

Integrate: 4y² - 4y

4y³/3 - 2y²

Limits 0 to 1

(4/3 - 2) - 0

-2/3

Volume = ⅔ pi

7 0
3 years ago
The sum of two numbers is 31.The product of the two numbers is 150. What are the two numbers?
Nikolay [14]
The two numbers I will call x and y.
x + y = 31
x * y = 150

You then solve for one variable in either equation and substitute it into the other equation.

x + y = 31
x = 31 - y

Then you plug it in:
x * y = 150
(31 - y) * y = 150
-y² + 31y = 150
y² - 31y + 150 = 0            Then factor:
(y - 6)(y - 25) = 0
y - 6 = 0        y - 25 = 0
y = 6             y = 25

When you plug y into the original equations, it comes out that the two numbers are 6 and 25. You can check your work because 6+25 = 31 and 6*25 = 150. Hope this helps! :)
5 0
3 years ago
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