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3 years ago

Which of the following is an arithmetic sequence?

Mathematics

1 answer:

Serhud [2]3 years ago

8 0

Answer:

Step-by-step explanation:

An arithmetic sequence is a series of numbers that increases or decreases by a certain quantity every step. A is not an arithmetic sequence, since it alternates between 2 and -2. B is not an arithmetic sequence, since it does not grow constantly in one direction. C is not an arithmetic sequence, but rather a geometric one. D is an arithmetic sequence, decreasing by 3 with each step. Hope this helps!

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What number must be added to the expression below to complete the square?

stiv31 [10]

D. 1/4

Explanation:

a perfect square is written in the form

$(x+a)^2 = x^2 + 2ax +a^2$ (1)

In our problem, we have this perfect square:

$x^2 - x + C$ (2)

with C being unknown. However, by comparing (1) and (2), we know that

$2a=-1$

So, we find

$a=-\frac{1}{2}$

and therefore, the missing term must be

$a^2 = \frac{1}{4}$

so the complete square is

$x^2 -x +\frac{1}{4}$

7 0

3 years ago

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How do you simplify radical 32

EleoNora [17]

$\sqrt{32}= \sqrt{16*2}= \sqrt{16}* \sqrt{2}=4 \sqrt{2}$

4 0

3 years ago

Max is painting a fence.The table shows the number of square feet he painted after various numbers of minutes. What is the rate

ohaa [14]

Answer:

3.5

Step-by-step explanation:

3 0

2 years ago

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Find the area 10ft 2 1/2

hichkok12 [17]

Answer:

if your trying to find the area of 10ft and 2 1/2 all you gotta do is turn the 2 1/2 in a decimal and multiply it by 10 which is 25

Step-by-step explanation:

6 0

3 years ago

Y is the midpoint of XZ .X has coordinates (2, 4), and Y has coordinates (-1, 1). Find the coordinates of z.

cricket20 [7]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
X&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
Z&({{ x}}\quad ,&{{ y}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{x+2}{2}~,~\cfrac{y+4}{2} \right)=\stackrel{Y}{(-1,1)}\implies 
\begin{cases}
\cfrac{x+2}{2}=-1\\\\
x+2=-2\\
\boxed{x=-4}\\
------\\
\cfrac{y+4}{2}=1\\\\
y+4=2\\
\boxed{y=-2}
\end{cases}$

7 0

3 years ago