All categories

3 years ago

Can you please help me with this

Mathematics

1 answer:

UNO [17]3 years ago

4 0

Parentheses. Exponents. Multiplication Division. Addition Subtraction.

2) 6 x (11 - 5)- 7^2
6 x (6) - 7^2
6 x 6 - 49
36 - 49
-13

3) (40 - 2^2) / (-4 + 6)
(40 - 4) / (-4 + 6)
(36) / (2)
36/2
13/1
13

4) (66 - 6) / 6 - 2^2
(60) / 6 - 2^2
60 / 6 - 4
60 / 2
30 / 1
30

You might be interested in

Solve for x<br><img src="https://tex.z-dn.net/?f=4%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%207x%20%2B%202" id="TexFormula1" title="4 {x

Alina [70]

$\bf 4x^2=7x+2\implies 4x^2-7x-2=0\implies (4x+1)(x-2)=0 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x\cdot x=\boxed{4x^2}~\hfill (1)(-2)=\boxed{-2}\hfill (4x\cdot -2)+(1\cdot x)=\boxed{-7x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 4x+1=0\implies 4x=-1\implies &x=-\cfrac{1}{4}\\[1em] x-2=0\implies &x=2 \end{cases}$

7 0

2 years ago

Consider the following hypothesis test: H0: μ1 - μ2 = 0 Ha: μ1 - μ2 ≠ 0 There are two independent samples taken from the two pop

nlexa [21]

Answer:

The value of the test statistic is $z = 1.78$

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

$\mu_1 = 110, s_1 = \frac{7.2}{\sqrt{81}} = 0.8$

Sample 2:

$\mu_2 = 108, s_2 = \frac{6.3}{\sqrt{64}} = 0.7875$

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

Distribution of the difference:

$X = \mu_1 - \mu_2 = 110 - 108 = 2$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{0.8^2+0.7875^2} = 1.1226$

What is the value of the test statistic?

$z = \frac{X - \mu}{s}$

$z = \frac{2 - 0}{1.1226}$

$z = 1.78$

The value of the test statistic is $z = 1.78$

5 0

3 years ago

Solve by factorizing x² + 8x + 15 + 0

shusha [124]

Download

GET

Algebra

Factor

Factor the polynomial.

(

)

(

)

Tap to view FREE steps...

()|[]√≥

789≤

456/^×>∩∪

123-+÷<π∞

,0.%=

Factor

Regroup terms.

Add

and

Factor

using the AC method.

Tap for fewer steps...

Consider the form

. Find a pair of integers whose product is

and whose sum is

. In this case, whose product is

and whose sum is

Write the factored form using these integers.

(

)

(

)

4 0

3 years ago

Read 2 more answers

Vanderbilt Corporation, which utilizes a calendar year as its fiscal year, is the payee on a $12,000, 7%, 8-month note receivabl

Vedmedyk [2.9K]

Given:
Payee: Vanderbilt Corporation
Notes Receivable from Stanford Company
<span>$12,000, 7%, 8-month

Debit Credit

October 1, 2016
Notes Receivable 12,000
Cash 12,000
*to record notes receivable from Stanford Company

December 31, 2016
Interest Receivable 560
Interest Income 560

12,000 * 7% * 8/12 = 560
*to recognize interest earned but not yet received

June 1, 2017
Cash 12,560
Notes Receivable 12,000
Interest Receivable 560
*to recognize full payment on note.</span>

3 0

3 years ago

What is the value of the expression -(-4)(-6)-3/5(10+15)

ladessa [460]

Answer:

-(-4)(-6)*3/5(10+15)

when there is a (-) in front of an expression in parentheses, change the sing of each term in the expression.

4*(-6)*3/5*(10+15)

Add the numbers (10+15)

4(-6)*3/5*25

multiplying an odd number of negative terms makes the product negative

-4*6*3/5*25

reduce the number with the greatest common factor 5

-4*6*3*5

calculate the product

solution

-360

8 0

3 years ago