Please help me to solve the problem
1 answer:
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I'm here buddy,
so, let's take the value of the two bags with equal weight as x.
= x + x + (x + ) =
= 3x + =
= 3x = -
( let's take the LCM of 4 and 5 = 20
= 3x = -
= 3x =
= x = ÷
=
×
=
So, the weight of the equal bags are and the weight of the third bag ( heavy one ) is
+
=
+
=
1st bag = kg
2nd bag = kg
3rd bag = kg
Hope it helps...
The price of the sweater was reduced by 40%
Step-by-step explanation:
Step 1; Cost before reduction was $20. The cost after reduction was 12$. Cost reduced= cost before reduction - cost after reduction
Cost reduced= $20 - $12 = $8
Step 2; We must find how much of the cost was reduced from the initial cost i.e. how much $8 is to $20. To do this we must convert it into a percentage. We divide the $8 with the $20 to get a value. This value must be multiplied with a 100 to be converted into a percentage.
Cost by which sweater was reduced= * 100 = 0.4 * 100 = 40
So the price of the sweater was reduced from $20 to $8 which equates to a reduction in 40%.