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exis [7]
3 years ago
13

Create 2 prisms with a volume of 300m3.

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

I will use two different type of prisms:

Triangular prism:

The volume is equal to the area of the triangle multiplied by the heigt of the prism.

So:

300m^3 = A*H

Suppose that the triangle is a triangle rectangle with two equal cathetus of lenght L = 6m, then the area of the triangle is:

A = 6m*6m/2 = 18m^2

300m^3 = 18m^2*H

H = 300/18 m = 16.6m

So this prism is a triangular prism where the area of the triangular face is 18m^2 and the height is 16.6m

Rectangular prism:

Here the volume of the prism is:

V = W*H*L

Where W is the width, H is the heigth and L is the length.

300m = W*H*L

now we can assign values to two of the values and then find the other value.

Suppose W = 30m, H = 5m

300m^3 = 30m*5m*L = 150m^2*L

L = 300/150 m = 2m

So this prism has a width of 30m, a height of 5m and a length of 2m.

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3 0
3 years ago
What is the answer for 7-2(8/2)+9
photoshop1234 [79]
7-2( \frac{8}{2} )+9 =

Remove parentheses:

7-2* \frac{8}{2} +9 =

7 - 2 * 4 + 9 =

7 - 8 + 9 =

= -1 + 9

= 8

hope this helps!



6 0
3 years ago
Caitlin has cut out a square piece of graph paper that contains a total of 81 blocks.How many blocks are there along one side of
FinnZ [79.3K]

Answer:

9 squares on each side of the square.

Step-by-step explanation:

\sqrt{81}=\sqrt{9\times 9}=\sqrt{9^2}=9

There are 9 equally sized blocks on one side of square piece of graph paper.

Best Regards!

5 0
3 years ago
What is the value of x?
nalin [4]

Answer:

  x = 42.9 m

Step-by-step explanation:

Corresponding sides of similar triangles MAB and MNP are proportional. This means ...

  x/MP = MA/MN

However, we don't have a number for MA yet, so we need to find it.

  MA +AN = MN

  MA = MN - AN            subtract AN

  MA = 67.2 m - 32 m = 35.2 m

Now, we can use this to find x.

  x = MP · (MA/MN) = (81.9 m) · 35.2/67.2

  x = 42.9 m

4 0
3 years ago
4x – 9y = 7 –2x 3y = 4 what number would you multiply the second equation by in order to eliminate the x-terms when adding to th
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