Pretty sure the answer is B. Hunting, as this will dwindle the population of elk.
According to the fact that <span>Josie was observing the roots of a monocot plant and it had thin, long roots, the type of growth which roots of monocots exhibit is being shown in the option : </span>a. primary growth. I think so because you can see the roots only during the process of <span>primary growth.
Do hope it helps!</span>
B) The grass height was the dependent variable.
E) Intermediate numbers of insects had the greatest positive impact on grass growth.
<h3>How insects affect the plant growth?</h3>
The grass height was the dependent variable because it depends on the nitrogenous waste of insects and presence of water. The numbers of insects had the greatest positive impact on grass growth because they provides nutrients to plant in the form of nitrogenous water so we can conclude that option B and E are the correct options.
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Answer:
No, Giardia is a protozoan that does not cause eosinophilia.
Explanation:
Eosinophilia refers to an increase in the number of eosinophils in the blood. The eosinophil is one of the white blood cells. When this occurs, the circulating eosinophils might be over 400 or 500.
Many factors might cause. One of them is parasite infections, in which helminths trigger the IgE generation, producing eosinophilia.
In the presence of the parasite antigen, eosinophils have a shorter medullar generation time, and they express a higher number of receptors for IgE and IgG. Their function is to damage the parasite, directly or indirectly, and to decrease the damages caused by their presence.
Giardia, among other protozoans, does not cause eosinophilia. Yet some other protozoans and parasites might induce it.
Answer:
A. 21 rad/s
B. 200.5 rpm
C. 26.46 rad/s2
D. 0.299 Hz
Explanation:
Parameters given are:
Tangential velocity,v = 1.26m/s
Diameter (outer edge) = 0.120m
Outer edge radius, ro = 0.12/2
= 0.06m
A. Calculate Angular velocity
Angular velocity, w = v/r
= v/ro
= 1.26/0.06 = 21 rad/s
In rpm,
2pi/60 rad/s = 1 rpm
1 rad/s = 60/2pi rpm
Sp, 21 rad/s = 60 * 21/2pi rpm
= 200.5 rpm
B. Calculate the inner edge radius, ri given w = 500 rpm
Converting rpm to rad/s,
= 2pi/60 * 500 rad/s
= 52.34 rad/s
ri = v/w
= 1.26/ 52.36
= 0.024m
C. Calculating centripetal acceleration, a from the outer edge, ro
a = v2/r = w2r
= (1.26)2/0.06
= 26.46 rad/s
D. Calculate the frequency, f of the outer edge angular velocity, w = 21 rad/s
f = 2pi/w
= 2pi/21
= 0.299 Hz (or per second)