okay 1 student = 1/20 chance of picking yellow
1/20 (30/30) = 30/600 chance of picking yellow out of 30 studnets
30/600 = 0.05 = 5% chance of choosing yellow.
I each studnet picks 1 yellow marker. Is that all the options?
Answer:
The objective of the problem is obtained below:
From the information, an urn consists of, 4 black, 2 orange balls and 8 white.
The person loses $1 for each white ball selected, no money is lost or gained for any orange balls picked and win $2 for each black ball selected. Let the random variable X denotes the winnings.
No winnings probability= 0.011
Probability of winning $1=0.3516
Probability of winning $2= 0.0879
Probability of winning $4= 0.0659
Step-by-step explanation:
or, 6m=5/13
or, m=5/13 ×6m
m=30/13
Answer:
r equals StartFraction C Over 2 pi EndFraction
Step-by-step explanation:
we know that
The circumference of a circle is equal to
where
r is the radius of the circle
Solve for r
That means -----> isolate the variable r
Divide by 2π both sides
Simplify right side
Rewrite
so
r equals StartFraction C Over 2 pi EndFraction
Answer:
your will be A
Step-by-step explanation:
hoped i helped and can i get brainiest pls
