A chord and a radius form an equilateral triangle.
The area of the larger segment is:
A = 5/6 r² π + r²√3/2 = 5/6 · 64 · 3.14 + 32 · 1.73 =
= 167.47 + 55.36 = 222.83 in²
The solution is <span>B. π/12+nπ
</span>proof
sinx cosx = 1/4 is equivalent to 2 <span>sinx cosx = 1/2 or sin2x =1/2
so 2x = arcsin(1/2) = </span>π/6 + 2nπ, so x = π/12+nπ
Answer:
wer here. Link below!
ly/3fcEdSx
bit.
Step-by-step explanation:
Answer:
f(x) = -x^2 + x + 13 find f(9) = -59
Hope this helps :)
