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3 years ago

Solve the proportion 5/x=4/8 is

1 answer:

7 0

D. 10 is your answer.
In order to solve a proportion, you cross multiply.
In this case it will be 40=4x
Solve for x is 10. Therefore D is your answer.
Please give 5 star if it helped you. :)

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List the members of P(fa, b, c, d}). Which are proper subsets of fa, b,c, d)?

ankoles [38]

Answer: As i understand, the set is P = {a,b,c,d}

then all the proper subsets are all the sets that belongs to P, that are different of P. Then A is a subset of P if all the elements of A belongs to P, but A is not equal to P

this is:

the sets of one element : {a}, {b}, {c}, {d} and the null set; ∅

sets of two elements: {a,b} , {a,c} , {a.d}, {b,c}, {b,d}, {c,d}

sets of three elements : {a,b,c}, {a,b,d}, {a,c,d}, {b,c,d}

and there arent sets of 4 elements or more.

6 0

3 years ago

Working in separately , three carpenters can make three chairs in three days. How many chairs can 7 carpenters working at the sa

tekilochka [14]

210chairs since the ratio is 3/3 which is 1/1 since 7 carpenters make 7 chairs every day for 30 days thats 7 * 30 which is 210

6 0

3 years ago

What is the missing coefficient in the equation 5x+By=2

meriva

Answer:

Where are the choices? The answer would be undefined.

Step-by-step explanation:

8 0

3 years ago

What properties can be used to solve 7y-15=-29. Identity property of multiplication,addition property of equality ,distributive

Sveta_85 [38]

Answer:

Addition Property of Equality.

Inverse property of multiplication.

Step-by-step explanation:

Given the equation:

$7y-15=-29$

First of all, let us use Addition Property of Equality.

According to the property, if we add a number on both sides of an equality, there is no change in the equality.

In other words, the equality will be same if we add the same number on Left Hand Side and Right Hand Side of the equality.

First of all, let us add 15 on both sides of the equality:

$7y-15+15=-29+15\\\Rightarrow 7y=-14$

Now, let us Inverse property of multiplication.

i.e. Multiplication of a number with its inverse is equal to 1.

$a\times \frac{1}{a} = 1$

So, let us multiply the given equation with $\frac{1}7$

$7y \times \dfrac{1}{7}=-14 \times \dfrac{1}{7}\\\Rightarrow 1y =-2\\\Rightarrow y=-2$

The properties used are:

Addition Property of Equality.

Inverse property of multiplication.

7 0

3 years ago

The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

:arrange the given data to get the range and median

1901 1902 1908 1910 1950 1952 1954 1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

the lower set of data=

1901 1902 1908 1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950 1952 1954 1955

we find the median of the upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920 1925 1928 1929 1930 1932 1933 1935

Minimum value= 1920

Maximum value= 1935

Range= 15 ( 1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920 1925 1928 1929

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930 1932 1933 1935

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

7 0

3 years ago