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3 years ago

Need help asap plz help dont have many points but ill give yu all i have if u help

Mathematics

1 answer:

Anna71 [15]3 years ago

4 0

Hello!

We can go through the choices and see if they are true

Choice 1
A function has one output for every input

This is not a function because it has -1 as an output for both 4 and -1

This is the answer
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Choice 2
The inputs are the x's

We see that the inputs are -1, 0, 3, and 4

This is true
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Choice 3
The outputs are the y's

We see the outputs are -2, -1, and 1

This is true
------------------------------------------------------------------------------------------------------
Choice 4
We can follow the lines and see the relations are

(-1, 1), (0, -2), (3, 1), (4, -1)

This is also true
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The only one that was false was the first choice so that is the answer

The answer is A) The diagram represents a function
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Hope this helps!

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miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

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3 years ago

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Fynjy0 [20]

Answer:

The Y-intercept is 1

It is where the line meets the y-axis

~PumpkinSpice1

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3 years ago

A triangular courtyard has a perimeter of 120 meters. The lengths of two sides are 30 meters and 50 meters. How long is the thir

Masja [62]

Answer:

the third side is 40 m long

Step-by-step explanation:

The perimeter of the triangle is the sum of its three sides, and they give you what that value in meters is (120 m)

Your are given the length of two of them: 30 m and 50 m, and need to find the third one (let's call it "x" for this unknown side)

Now set the following equation:

Perimeter = side 1 + side 2 + side 3 --> replace these with the info you know

120 m = 30 m + 50 m + x --> add 30 m and 50 m obtaining 80 m

120 m = 80 m + x --> now solve for x (isolate the x on one side) by subtracting 80 m from both sides

120 m - 80 m = x --> perform the subtraction 120 m - 80 m = 40 m

40 m = x

Which tells us that the third unknown side has a length of 40 m

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4 years ago

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⚠URGENT!!!⚠ solve for m.

Zinaida [17]

Answer:

Step-by-step explanation:

Remark

Read the following carefully.

There is a beautiful theorem that has to do with the endpoints of two angles sharing the same endpoints.

To be a little clearer, I hope, that makes < BAC = <BDC because both angles have B and C as their endpoints inside the circle. Make sure you understand that statement before moving on.

For this problem <BDC = <CAB = 33 degrees.

That means that ADC = 37 + 33 = 70

Solution

<ADC and CBA are opposite angles.

That means that they add to 180

From the above statement in the Remark section <ADC = 37 + 33 = 70 degrees <ABD + <DBC = <ABC = m + 71

<ABC + ADC = 180

m + 71 + 70 = 180 Combine

m + 141 = 180 Subtract 141 from both sides.

m+141-141= 180 - 141 Combine

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Answer: m = 39

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