1. 8.96 x 105 I think
2. <span>4.25 x 10-4
</span>
I think we need a coordinate grid for that,,
All except combine like terms. Since you only have 1 variable.
Hope this helps.
r3t40
Answer:
The required drawing showing the cliff, river, and tower as well as the details in the question is attached, please find alongside the answer
The width of the river is approximately 51.55 meters
Step-by-step explanation:
The height of the observation tower = 11 meters
The angle of elevation of the cliff top and the opposite side of the river = 20°
The angle of elevation of the tower top and the opposite side of the river = 30°
Therefore, by sine rule, we have;
h/sin(20) = w/sin(60)
11/sin(10) = length, l/sin(60)
l = sin(60) ×11/sin(10) ≈ 54.86 meters
w = l × cos (20) = 54.86 meters × cos (20) ≈ 51.55 meters
The width, w, of the river is approximately 51.55 meters.
Answer:
48
Step-by-step explanation:
because I had times 12 and 4 to get 48