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3 years ago

Four times the sum of some number plus 2 is equal to 8 times the number minus 16.

Mathematics

2 answers:

mezya [45]3 years ago

8 0

Answer:

x=9/2

Step-by-step explanation:

4x+2=8x-16

-4x=-18

4x=18

x=18/4

x=9/2

kicyunya [14]3 years ago

6 0

Answer: 9/2
.........

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Answer:

I think Jenny will be able to do 9 pillows with the lace trim.

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3 years ago

Does anyone know this??

blagie [28]

Answer:

x = 38, y = 4

Step-by-step explanation:

Since AB = BC then the triangle is isosceles and the base angles are congruent, that is

∠ DAB = ∠ DCB = 52°

Subtract the sum of the base angle from 180° for ∠ ABC

∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°

Note that ∠ ABD = ∠ CBD, thus

x = 76 ÷ 2 = 38

BD bisects the side AC, thus DC = AD = 4

Thus y = 4

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3 years ago

The surface area of a cube that is 8 yards of width and length?

Umnica [9.8K]

Answer:

Step-by-step explanation:

The formula of a surface area of a cube:

$SA = 6a^2$

We have a = 8 yd.

Substitute:

$SA=6(8^2)=6(64)=384\ yd^2$

8 0

3 years ago

Which applies the power of a product rule simplify

liberstina [14]

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3 years ago

Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. The

Tems11 [23]

Answer:

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

They randomly survey 387 drivers and find that 298 claim to always buckle up.

This means that $n = 387, \pi = \frac{298}{387} = 0.77$

84% confidence level

So $\alpha = 0.16$ , z is the value of Z that has a p-value of $1 - \frac{0.16}{2} = 0.92$ , so $Z = 1.405$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8$

The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).

6 0

3 years ago