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3 years ago

Four times the sum of some number plus 2 is equal to 8 times the number minus 16.

Mathematics

2 answers:

mezya [45]3 years ago

8 0

Answer:

x=9/2

Step-by-step explanation:

4x+2=8x-16

-4x=-18

4x=18

x=18/4

x=9/2

kicyunya [14]3 years ago

6 0

Answer: 9/2
.........

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Help im super confused on this question

Verizon [17]

Answer:

⦿ (7, 2)

Step-by-step explanation:

Try each solution in both inequalities and see which solution makes both inequalities true.

4x + 2y > 8

x - y ≥ 2

A. (2, 4)

4(2) + 2(4) > 8

16 > 8 True

2 - 4 ≥ 2

-2 ≥ 2 False

B. (4, 0)

4(-4) + 2(0) > 8

-16 > 8 False

C. (7, 2)

4(7) + 2(2) > 8

32 > 8 True

7 - 2 ≥ 2

5 ≥ 2 True

D. (1, -3)

4(1) + 2(-3) > 8

-2 > 8 False

Answer: C.

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1 year ago

Kamden is a mind-reading alien. He had each friend draw and look at a card, then he guessed whether the card had a star on it.

yulyashka [42]

The completed table will have values filled into it accordingly from left to right and the downwards.

<h3>What values are required to complete the table?</h3>

The concept of relative frequencies involves expressing the frequency of occurrence of events as a fraction of a whole frequency.

Hence, it follows that the blank space on the top-leftmost corner of the table can be filled with the value; 4/5 = 0.8.

For the top-rightmost blank space in the table, the required value is; 2/754 = 0.0027.

For the bottom-leftmost blank space, the required value to fill the table is; 1/5 = 0.2.

For the bottom-rightmost blank space, the required value is; 752/754 = 0.9973.

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1 year ago

A 20-ounce bag of popcorn costs $2.80. If the unit price stays the same, how much does a 35-ounce bag of popcorn cost?

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Answer:

I think the answer is C

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2 years ago

Which of the following is equal to the expression above

EleoNora [17]

Answer:

$15 \sqrt[3]{2}$

Step-by-step explanation:

${(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}$

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3 years ago