Answer:
Area of 
ACD = 4 
Area of ABC = 16
Step-by-step explanation:
Given that:
D is a point on AB.
and ABC is a triangle.
AD:DB = 1 : 3
Area of CDB = 12
Kindly refer to the attached image as per the given dimensions and values.
To find:
Area of ACD and Area of ABC = ?
Solution:
Formula for area of a triangle = 
The altitudes of triangles CDB and ACD are equal in dimensions.
Therefore the area of triangles CDB and ACD will be equal to the ratio of their bases.
Area of ACD : Area of CDB = AD: DB = 1 : 3
Area of ACD = 
Area of ABC = Area of ACD + Area of CDB = 12 + 4 = <em>16</em>
Therefore, the answer is:
Area of ACD = 4
Area of ABC = 16
Answer:
cl + 1/(N+1)
Step-by-step explanation:
If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl
And we know that the (N+1)th harmonic number can be found by doing
1+1/2+1/3+1/4+...+1/N+1/(N+1)
=cl + 1/(N+1)
The (N+1)th harmonic number is cl + 1/(N+1) given that the Nth term is cl
Other way to see the answers:
Maybe you want to write it as a single fraction so you have
[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)
3/5 I think sorry if I’m wrong
Answer:
18
Step-by-step explanation:
Answer:
once
Step-by-step explanation:
The vertical line test shows how many outputs (y-value) there are for one input (x-value). There can only one output for each input because only one value should satisfy an equation that represents a function. If the vertical line goes through the graph twice, that shows there are two outputs for a single x-value. This would mean it is not a function.
