The answer is (C) IT careers are found in a wide variety of industries.
Nowadays, all types of industries in various different parts of the world will have an IT (information technology) department because it is needed, since most businesses operate using some form of IT equipment, which, most commonly found is a computer. It is a particularly lucrative field because of the wide array of job availability.
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
char Keep_Going = '-';
int nextBid = 0;
srand(5);
while (Keep_Going != 'n') { //<-- solution
nextBid = nextBid + (rand()%10 + 1);
cout << "I'll bid $" << nextBid << "!" << endl;
cout << "Continue bidding? ";
cin >> Keep_Going;
}
cout << endl;
return 0;
}
For each call of a function, the python virtual machine must allocate a small chunk of memory on the call stack, which is known as <u>stack frame.</u>
<u></u>
<h3>What Does Stack Frame Mean?</h3>
A stack frame is a memory management technique used in some programming languages for generating and eliminating temporary variables. In other words, it can be considered the collection of all information on the stack pertaining to a subprogram call.
Stack frames are only existent during the runtime process. Stack frames help programming languages in supporting recursive functionality for subroutines.
A stack frame is comprised of:
- Saved copies of registers modified by subprograms that could need restoration
Learn more about stack frame
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Answer:
void mn(int m, int n){
int sum = 0;
int count = 0;
if(m<n){
for(int i = m;i<=n;i++){
sum+=i;
}
}
else{
for(int i = n;i<=m;i++){
sum+=i;
}
}
count = abs(m - n)+1;
cout<<"Sum: "<<sum<<endl;
cout<<"Average: "<<(float)sum/count;
}
Explanation:
This line defines the method
void mn(int m, int n){
This initializes sum and count to 0
int sum = 0;
int count = 0;
This checks if m is less than n
if(m<n){
This iterates from m to n and calculates the sum of numbers between this interval
<em> for(int i = m;i<=n;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
If otherwise,
else{
This iterates from n to m and calculates the sum of numbers between this interval
<em> for(int i = n;i<=m;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
This calculates the range from m to n using absolute function
count = abs(m - n)+1;
This prints the calculated sum
cout<<"Sum: "<<sum<<endl;
This calculates and prints the average
cout<<"Average: "<<(float)sum/count;
}
<em>See attachment for complete program that includes the main (in c++)</em>
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