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MrRa [10]
3 years ago
14

Write the equation of a line in SLOPE-INTERCEPT FORM that goes through (7,-3) and (6,-8).

Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0

Slope formula: y2-y1/x2-x1

-8-(-3)/6-7

-5/-1

5

Find the y-intercept with the formula for slope intercept form.

y = mx + b

-3 = 5(7) + b

-3 = 35 + b

-3 - 35 = 35 - 35 + b

-38 = b

Fill in what we have:

y = 5x - 38

Best of Luck!

svet-max [94.6K]3 years ago
3 0

Answer:

y = 5x-38

Step-by-step explanation:

The slope is m = (y2-y1)/(x2-x1)

                          = (-8 - -3)/(6-7)

                          = ( -8+3)/(-1)

                           =-5/-1

                            =5

Slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

y = 5x+b

Substitute a point into the equation

-8 = 5(6) +b

-8 = 30+b

-8-30 = 30-30+b

-38 = b

y = 5x-38

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Find the product of 27×6×60 then explain how you would use mental math to find the product of 27×600
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27x6x60=9,720                                                                                                      *You can use mental math by multiplying 27 by 6 and adding the 2 zeros to the end of the product*





7 0
2 years ago
Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

7 0
3 years ago
Amaya is excited to go to the used video game store to buy a game system later today. The game system usually costs x dollars, b
Ksenya-84 [330]

Answer:

x(85/100)

Step-by-step explanation:

100-15 = 85

x(85/100)

5 0
2 years ago
Read 2 more answers
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
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