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2 years ago

Plz answer these questions. If ur gonna answer answer them all or else i will report and u wont get brainliest.

Mathematics

2 answers:

o-na [289]2 years ago

8 0

Answer:

Step-by-step explanation:

lawyer [7]2 years ago

6 0

Answer:

1: 1.5, a decrease

2: 5, decreases, 4.1, decreases, 4

3: 694, 708, other, faster

4: A, 45

5: B

Step-by-step explanation:

Surprised that I'm not stealing points?

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I don’t understand this someone pls help

omeli [17]

To solve this, you need to plug in the numbers for h.

-4(-12) ≥ 8 48 ≥ 8 yes

-4(-7) ≥ 8 28 ≥ 8 yes

-4(-5) ≥ 8 20 ≥ 8 yes

-4(-3) ≥ 8 12 ≥ 8 yes

-4(-2) ≥ 8 8 ≥ 8 yes

-4(-1) ≥ 8 4 ≥ 8 no

-4(1) ≥ 8 -4 ≥ 8 no

-4(3) ≥ 8 -12 ≥ 8 no

-4(8) ≥ 8 -32 ≥ 8 no

Hope this helped!

7 0

2 years ago

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

egoroff_w [7]

Answer:

no solution

Step-by-step explanation:

X cannot equal itself minus 5, in the same way if we replace it by let's say, 6...

6 does not equal 6-5 (1)........ and by the way in this specific equation 6 is just an example it does not matter what you replace it with, x can never = x-5

Hope this helped! Good Luck!

5 0

2 years ago

What is the equation for the plane illustrated below?

TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

$a\cdot x + b\cdot y + c\cdot z = d$

Where:

$x$ , $y$ , $z$ - Orthogonal inputs.

$a$ , $b$ , $c$ , $d$ - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0), (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

$y = m\cdot x + b$

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - x-Intercept, dimensionless.

If $x_{1} = 2$ , $y_{1} = 0$ , $x_{2} = 0$ and $y_{2} = 2$ , then:

Slope

$m = \frac{2-0}{0-2}$

$m = -1$

x-Intercept

$b = y_{1} - m\cdot x_{1}$

$b = 0 -(-1)\cdot (2)$

$b = 2$

The equation of the line in the xy-plane is $y = -x+2$ or $x + y = 2$ , which is equivalent to $3\cdot x + 3\cdot y = 6$ .

yz-plane (0, 2, 0) and (0, 0, 3)

$z = m\cdot y + b$

$m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}$

Where:

$m$ - Slope, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

If $y_{1} = 2$ , $z_{1} = 0$ , $y_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

y-Intercept

$b = z_{1} - m\cdot y_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the yz-plane is $z = -\frac{3}{2}\cdot y+3$ or $3\cdot y + 2\cdot z = 6$ .

xz-plane (2, 0, 0) and (0, 0, 3)

$z = m\cdot x + b$

$m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - z-Intercept, dimensionless.

If $x_{1} = 2$ , $z_{1} = 0$ , $x_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

x-Intercept

$b = z_{1} - m\cdot x_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the xz-plane is $z = -\frac{3}{2}\cdot x+3$ or $3\cdot x + 2\cdot z = 6$

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

$a = 3$ , $b = 3$ , $c = 2$ , $d = 6$

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

8 0

2 years ago

Find the highest common factor of 28 and 210 Step by step Please help

Yuri [45]

Hello there!

To find the GCF, we must list all the factors and then just spot the greatest factor.

28: 1, 2, 4, 7, 14, 28.

210 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70.

So 14 is the GCF. Hope this helps you!

~Just a felicitous girlie

#HaveAnAwesomeDay

$SilentNature$

7 0

2 years ago

After spending 5/9 of his money, David has $36 left. How much money did he have at first?

liq [111]

81 dollars at first

8 0

2 years ago