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3 years ago

Solve. 3x = 15 A) x = 4 B) x = 5 C) x = 6 D) x = 12

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

Answer:

Step-by-step explanation:

3x=15

Divide both sides by 3 to isolate the x variable.

x=15/3=5

Neko [114]3 years ago

3 0

Answer:

Step-by-step explanation:

Given 3x = 15, solve for x.

To do this, divide both sides of the equation by 3, returning

x = 5.

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Studentka2010 [4]

Answer:

$4x^{3} y^{2} (\sqrt[3]{4 x y})$

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

$\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }$

Then we'll extract the 4 from the cubic root. We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

$\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }$

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

$4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }$

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

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The answer is then:

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Most of the information's required for solving the question is already given in the question.
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