All you can do to this expression is simplify.
You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:
Therefore your end result is:
The answer to the question is A
Answer:
11/4 seconds
Step-by-step explanation:
We can see from the given equation that the height at the diving board is h = 3.
This is because the h(t) equation has that +3 at the end, which denotes the initial height of the diver, the height when he is standing on the board before jumping.
To find where h(t) = 3 is true, we need to set h(t) equal to 3 and solve for t.
h(t) = 3
h(t) = -4t^2 + 11t + 3 = 3
-4t^2 + 11t + 3 - 3 = 0
-4t^2 + 11t = 0
t*(-4t + 11) = 0
so h(t) = 3 when t = 0 and when t = 11/4 sec
we already know that at t = 0 the height is 3, it is the initial height given from the equation, so we want to use the other solution for t.
the diver is back at the height of the diving board at t = 11/4 sec
The 3rd number line, (the one farthest to the right) is the line graph that shows the locations required.
If you need me to explain, just let me know!
