Answer:
You can increase your precision in the lab by paying close attention to detail, using equipment properly and increasing your sample size. Ensure that your equipment is properly calibrated, functioning, clean and ready to use.
Explanation:
As the Earth moves around the sun during a year, the northern half of the Earth is tilted towards the sun in the summer, making daytime longer than night. In winter, this reverses; the earth tilts away from the sun and nighttime becomes longer
3. Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2 H₂O represents a neutralization reaction.
<u>Explanation:</u>
Neutralization reaction is a reaction in which an acid reacts with a base to form a slat and water.
First reaction is the decomposition reaction in which the reactant is decomposed to form 2 or more products.
Second one is the combustion reaction in which methane is burnt in presence of oxygen.
Third one is the Neutralization reaction, in which calcium hydroxide (base) reacts with sulfuric acid (acid) to form a (salt) calcium sulfate and water.
Fourth reaction is nothing but the double displacement reaction in which the ions exchanged their positions there by forming two new products.
The balanced reaction: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
We first convert volume of C2H6 to no. of moles. We use the conditions at STP where 1 mol = 22.4 L thus,
Moles C2H6 = 16.4 L/ 22.4 L =0.7321 mol
In order to determine the limiting reagent, we look at the given amounts of the reactants.
0.7321 mol C2H6 (7/2 mol O2 / 1 mol C2H6) = 2.562 mol O2
From the given amounts of the reactants, we can say that O2 is the limiting reactant since we need 2.562 mol O2 to completely react the given amount of C2H6. The excess reagent is C2H6
To calculate for the amount of products and excess reactants:
0.980 mol O2 (2 mol CO2 / (7/2 mol O2)) = 0.56 mol CO2 (22.4 L / 1 mol ) =12.544 L CO2
<span>0.980 mol O2 (1 mol C2H6 / (7/2 mol O2)) = 0.28 mol C2H6
Excess C2H6 = 0.7321 mol - 0.28 mol C2H6 = 0.4521 mol C2H6
We then use the molecular weight of C2H6 to convert the excess amount to grams.
0.4521 mol C2H6 (30.08 g C2H6 / 1 mol C2H6) = <span>13.60 g C2H6
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<span>Since the limiting reagent is O2 there will be no oxygen atoms that will be left after the reaction.</span>
