Answer:
5.64×10²³ atoms C
Explanation:
Convert moles of H to moles of C:
2.81 mol H × (2 mol C / 6 mol H) = 0.937 mol C
Convert moles of C to atoms of C:
0.937 mol C × (6.02×10²³ atoms C / mol C) = 5.64×10²³ atoms C
Answer:
Work done in this process = 4053 J
Explanation:
Mass of the gas = 0.092 kg
Pressure is constant = 1 atm = 101325 pa
Initial temperature 
= 200 K
Final temperature 
= 200 - 85 = 115 K
Gas constant for nitrogen = 297 
When pressure of a gas is constant, volume of the gas is directly proportional to its temperature.
⇒ V ∝ T
⇒ 
= 
------------ ( 1 )
From ideal gas equation 
= m R ------ (2)
⇒ 101325 × = 0.092 × 297 × 200
⇒ = 0.054 
This is the volume at initial condition.
From equation 1
⇒ 
= 
⇒ 
= 0.094
This is the volume at final condition.
Thus the work done is given by W = P [ - ]
⇒ W = 101325 × [ 0.094 - 0.054]
⇒ W = 4053 J
This is the work done in that process.
Answer:
F=ma
Explanation:
F=m×a
according to that F÷m=a and also F ÷a=m
Answer:
a) equilibrium shifts towards the right
b) equilibrium shifts towards the right
c) equilibrium shifts towards the left
d) has no effect on equilibrium position
e) has no effect on equilibrium position
Explanation:
A reversible reaction may attain equilibrium in a closed system. A chemical system is said to be in a state of dynamic equilibrium when the rate of forward reaction is equal to the rate of reaction.
According to Le Chateliers principle, when a constraint such as a change in temperature, pressure, volume or concentration is imposed upon a system in equilibrium, the equilibrium position shifts in such a way as to annul the constraint.
When the concentration of reactants is increased, the equilibrium position is shifted towards the right hand side and more products are formed. For an endothermic reaction, the reverse reaction is favoured by a decrease in temperature. Increase in pressure has no effect on the system since there are equal volumes on both sides of the reaction equation. Similarly, the addition of a catalyst has no effect on the equilibrium position since it speeds up both the forward and reverse reactions to the same extent.
