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4 years ago

Which graph represents the linear function y=-2x+3

Mathematics

1 answer:

klasskru [66]4 years ago

5 0

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Emanuel has 745 pictures in his phone.His memory is getting full so he starts deleting 20 pictures every day.Define each variabl

IceJOKER [234]

One variable is the amount of days. Lets call the amount of days D. Another variable is the amount of pictures left. Lets call this p. In this case, since Emanuel is deleting 20 pictures a day, and he has 745 picture to start with, the equation would be 745- 20D=p.

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4 years ago

Read 2 more answers

If ax + x^2 = y^2 -at , what is the value or x and y?

alexandr1967 [171]

Answer:

dx. = yex ⇒ dy y. ∫. = x ... 2 xx dx. ∫. , i.e. yx = 4. 4 x c. +. Hence y = 3. 4 x c x.

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3 years ago

Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)

Law Incorporation [45]

Answer:

$Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}$

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

$Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}$

Direction of the sum of the vectors:

$\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\$

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3 years ago

For the function F(x) = 1/x-2, which of these could be a value of F(x) when xis

dusya [7]

The answer to this question is C

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3 years ago

Alex bought four 15-pound bags of dog food, three 4 1/2 pound bags of cat food, and two 1/2-pound bags of fish food. How many po

garri49 [273]

Answer:

15+4.5+0.5=20

Alex bought 20 pounds of pet food

Step-by-step explanation:

Hope this helps!!

BTW...if y'all have any questions for school (it can be any grade level or subject) just comment here and I will get to it as soon as I can!! ❤

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3 years ago