Answer:
Slope
0.33
Step-by-step explanation:
Riffshckckcjvcjdid djcudbdurbfbtbtbrjkfjf Fuzhou undid hey hbu gang vlivh bang
Answer: I think it's B but i might be wrong
Answer:
$51 saved.
Step-by-step explanation:
Well 12% of $425 is found by multiplying
(.12)(425) = $51 saved.
Answer:

Step-by-step explanation:
Let <em>A</em> be the event of getting an odd number.
<em>P(A)</em> be the probability of getting an odd number.
Total odd numbers here are 6 i.e. 
Here, total numbers in the game are 12 i.e
.
Formula for probability of an <em>event E</em> can be observed as:


Let <em>B</em> be the event of getting 11.
<em>P(B)</em> be the probability of getting 11.
Total number of possible cases is 1.

is the probability that we get 11 and an odd number.
Possible number of cases = 1

<em>P(B/A)</em> is the probability that we get an 11 given that it is an odd number.

Hence, P(B/A) = 