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zzz [600]
3 years ago
5

If the temperature is 10 above zero in the morning, and 17 below zero in the evening, what was the difference in temperature for

the day? Show calculator
Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0

Hi!

We can find the result by subtracting the minimum value from the maximum value, that's the value of the difference in the temperature for the day, and it is calculated like this:

10 - (-17) = 10 + 17 = 27

Hope this helps!

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A cylinder with a radius of 12cm and a height of 20cm has the same volume as a cone with a radius of 8cm. What is the height of
ivanzaharov [21]

Answer: 135cm

Step-by-step explanation

Volume of a cylinder = πr²h

Volume of a cone. = 1/3πr²h

The two shapes are both solid shapes.

Since the have same volume, we can then equate the two together and solve for the height of the cone.

Now make H the height and R the radius of the cylinder and h the height and r the radius of the cylinder.

Now equating the two

πR²H = 1/3πr²h

Now substitute for the values now

Multiply through by 3

3πR²H = πr²h

But π is common so it could be obliterated from the equation

3R²H = r²h

3 x 12² x 20 = 8² x h

3 x 144 x 20 = 64 x h

60 x 144 = 64h

8640. = 64h

Therefore

h = 8640/64

= 135cm

8 0
3 years ago
What is the surface area of the cylinder with height 2 yd and radius 3 yd? Round your answer to the nearest thousandth.
olasank [31]
<h2>Given :</h2>

  • height (h) = 2 yd

  • radius (r) = 3 yd

<h2>Solution :</h2>

\boxed{ \mathrm{Surface \:  Area = 2\pi r(h +r )}}

  • 2 \times 3.14 \times 3 \times (3 + 2)

  • 18.84 \times 5

  • \boxed{\mathrm{94.2 \: yd {}^{2} }}

_____________________________

\mathrm{ \#TeeNForeveR}

3 0
3 years ago
What is the value of x?
kotegsom [21]

Answer:

X=15

Step-by-step explanation:

A +B + C = 180

2x +4x+ 6x = 180

12x =180

X= 15

4 0
3 years ago
7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54
Levart [38]
7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}
5 0
3 years ago
What is the area of the medal platform?
Pani-rosa [81]
The total area is 78 sq. ft.

Since the medal platform has different measurements, we need to individually compute the area of each polygon.

The top polygon is a square. Its sides measure 3 ft. 

A₁ = a²
A₁ = 3 ft²
A₁ = 9 ft²

The middle polygon is a rectangle. 

Its total width can be derived by adding the widths given and the width of the square above.

w = 3 ft + 3 ft + 3 ft
w = 9 ft

A₂ = width * height
A₂ = 9 ft * 2 ft
A₂ = 18 ft²

The bottom polygon is also a rectangle.

w = 4 ft + 9 ft + 4 ft
w = 17 ft

A₃ = width * height
A₃ = 17 ft * 3 ft
A₃ = 51 ft²

Total Area = A₁ + A₂ + A₃
T.A. = 9 ft² + 18 ft² + 51 ft²
T.A. = 78 ft²
3 0
3 years ago
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