6 < c < 20,

Of course if you knew the triangle was a right triangle you could use the Pythagorean theorem to directly get the size of the third side.

3 0

3 years ago

Pllsss help

alexgriva [62]

Answer:

A. |x|=9 D. -|-x|=-9 F. |-x|=9

Step-by-step explanation:

a. |9|=9

D. -|9| = -9

F. 9=9

7 0

3 years ago

Y=x2-2x-5<br> Change to vertex form

MaRussiya [10]

The vertex form is $y=(x-1)^{2} -6$

Step-by-step explanation:

The given equation $y=x^{2} -2x-5$ is a parabola. The vertex of the parabola is of the form $y=ax^{2} +bx+c$

The parameters of the parabola are $a=1, b=-2$ and $c=-5$

The vertex of the x-coordinate is given by $x=\frac{-b}{2a}$

Thus, substituting the values of a and b in $x=\frac{-b}{2a}$ , we get,

$\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}$

Now, substituting $x=1$ in $y=x^{2} -2x-5$ , we get,

$\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}$

Thus, the vertex is $(1,-6)$

The equation of parabola to be in vertex form is $y=a(x-h)^{2} +k$

where a is the coefficient of $x^{2}$ , h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, $a=1, h=1$ and $k=-6$

Thus, substituting the values in the equation of the vertex form,

$y=1(x-1)^{2} -6\\y=(x-1)^{2} -6$

Hence, the vertex form is $y=(x-1)^{2} -6$

8 0

4 years ago