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rodikova [14]
3 years ago
5

Find f(x) + g(x) when f(x) = 2x^2 + x and g(x) = 3x + 2

Mathematics
2 answers:
Artyom0805 [142]3 years ago
8 0

Answer:

2x^2 + 4x+2

Step-by-step explanation:

f(x) = 2x^2 + x and g(x) = 3x + 2

f(x) + g(x) =  2x^2 + x + 3x + 2

            Combine like terms

               = 2x^2 + 4x+2

kupik [55]3 years ago
8 0

Answer:

f(x)+g(x)=2x^2+4x+2

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+x\text{ and } g(x)=3x+2

And we want to find:

f(x)+g(x)

So, substitute:

=(2x^2+x)+(3x+2)

Combine like terms:

=2x^2+(x+3x)+2

Add:

=2x^2+4x+2

So:

f(x)+g(x)=2x^2+4x+2

And we're done!

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Can someone explain how to convert 70kg to lbs? i need to show work on my test.
Jlenok [28]

Answer:

70 kg is 154.3 lbs.

Step-by-step explanation:

There is 0.453592 kilograms per pound. That is just the conversion rate.

To find how many lbs 70 kg is, we do 70/0.453592 which is 154.3236.

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3 years ago
K over x = w over v solve for x
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3 years ago
A line segment that forms a right angle with another segment at its midpoint
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 52% of all such batches contain no defect
koban [17]

Answer:

P ( B0 / D0 ) = 0.59877

P ( B1 / D0 ) = 0.25793

P ( B2 / D0 ) = 0.14329

Step-by-step explanation:

Given:

-  0 be the event that the batch has 0 defectives = (0 ) = 0.52

- 1 be the event that the batch has 1 defectives = (1 ) = 0.28

- 2 be the event that the batch has 2 defectives = (2 ) = 0.2

- Two components are selected

Find:

What are the probabilities associated with 0, 1, and 2 defective components being in the batch under each of the following conditions?

(a) Neither tested component is defective.

Solution:

Let 0 be the event that neither selected component is defective.

- The event 0 can happen in three different ways:

(i) Our batch of 10 is perfect, and we get no defectives in  our sample of two;

                   P(i) = P(B0) = 0.52

(ii) Our batch of 10 has 1 defective, but our sample of two misses them;

                  P ( no defect / B1 ) = P ( no defect ) / P ( B 1 )

                                                  = 9C2 / 10C2 = 0.8

                  P ( ii ) = 0.28*0.8 = 0.224

(iii) Our batch  has 2 defective, but our sample misses them.

                 P ( no defect / B2 ) = P ( no defect ) / P ( B 2 )

                                                  = 8C2 / 10C2 = 56/90

                  P ( iii ) = 0.2*56/90 = 0.124444

- Then,

                 P(Do) = P(i) + P(ii) + P(iii)

                 P(Do) = 0.52 + 0.224 + 0.124444 = 977/1125

We use the general conditional probability formula:

                P ( B0 / D0 ) = P ( B0 & D0 ) / P( D0 )

                P ( B0 / D0 ) = 0.52*1125 / 977 = 0.59877

                P ( B1 / D0 ) = P ( B1 & D0 ) / P( D0 )

                P ( B1 / D0 ) = 0.224*1125 / 977 = 0.25793

                P ( B2 / D0 ) = P ( B2 & D0 ) / P( D0 )

                P ( B2 / D0 ) = 0.12444*1125 / 977 = 0.14329

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3 years ago
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Ber [7]

Answer:

A-B=x^2-x+1

Step-by-step explanation:

A-B=3x^2+5x-6+(-2x^2-6x+7)

 =3x^2+5x-6-2x^2-6x+7

 =x^2-x+1

5 0
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