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2 years ago

Please answer use pic

Mathematics

1 answer:

Firdavs [7]2 years ago

3 0

Answer:

Step-by-step explanation:

Because the theoretical probability is greater than the experimental probability

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Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?

zhuklara [117]

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

3.30 = 3.30

4 0

3 years ago

How to find the perimeter ratio of two similar triangles

Free_Kalibri [48]

Answer:

of their perimeters is equal to the ratio of their corresponding side lengths. ratio of their areas is equal to the square of the ratio of their corresponding side lengths.

5 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago

Help please!!!

Y_Kistochka [10]

1. I feel the need to explain things first before I write the numeric value.
Let x be the total number of students in the school. 25% of this value is given to be 35.
(0.25)x = 35
The value of x is 140. 75% of this value is the answer which is equal to 105.

2. Let y be the alternative schools. With this, the number of charter schools is 2x - 6 which is equal to 52
2x - 6 = 52
The value of x is 29. Therefore, there are 29 charter schools.

4 0

3 years ago

Find the perimeter of a square with area 64 cm/2

finlep [7]

The answer is 32cm :))))))

8 0

3 years ago

Read 2 more answers