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ipn [44]
3 years ago
7

Find the vertex of the following parabola. please write your answer in the form: (x,y) with no spaces. (So a vertex of 2,1 would

be written as (2,1)).
Show all your work.

Mathematics
1 answer:
Komok [63]3 years ago
4 0

Answer:

Vertex (-3,1)

Step-by-step explanation:

y = x^2 + 6x + 10          Put brackets around the first two terms

y = (x^2 + 6x) + 10        Take 1/2 the linear term (6) and square it. Put that inside  the brackets. Always add.

y = (x^2 + 6x + (6/2)^2 ) + 10 Since you added in side the brackets, subtract after the 10

y = (x^2 + 6x + 9) + 10 - 9     The 3 terms inside the brackets are a perfect square. Combine the two terms outside the brackets.

y = (x + 3)^2 + 1

The vertex is at (the value that makes x + 3 go to zero, and the number outside the brackets)

(-3,1)

Check

The check is to ask Desmos to graph the equation. That graph is shown below. Notice that the lowest point is(-3,1). Notice that the graph and my answer do agree.

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A number divided by -9 is 16. What is the missing number?
kondor19780726 [428]
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7 0
3 years ago
Read 2 more answers
What is the solution of x+8/5x-1>0?
DerKrebs [107]

Answer:

x<-8 or x>1/5

Step-by-step explanation:

\frac{x+8}{5x-1} >0

First we replace > symbol by = sign

\frac{x+8}{5x-1} =0

To solve for x we multiply 5x-1 on both sides

x+8 =0

x=-8

5x-1=0 solve for x

x= 1/5

WE got two values x=-8  and x= 1/5

Now we make a number line and check with each interval

x<-8,  -8<x<1/5,  x>1/5

Pick x= -9 and check with the given inequality

\frac{-9+8}{5(-9)-1} >0

1/46 >0 is true, so x<-8 satisfies our inequality

Pick x= 0 and check with the given inequality

\frac{0+8}{5(0)-1} >0

-8 >0 is false , -8<x<1/5 does not satifies our inequality

Pick x= 2 and check with the given inequality

\frac{2+8}{5(2)-1} >0

10/9>0 is true , x>1/5  satisfies our inequality

3 0
3 years ago
Read 2 more answers
Solve |12x + 1| = 10<br> (9/2, 11/2)<br> (-9/2, 9/2)<br> (-112.9/2)
Reil [10]

|12x + 1| = 10

Remove the absolute value term and make two equations:

12x +1 = 10

12x +1 = -10

Now solve for both x values:

12x +1 = 10

Subtract 1 from both sides:

12x = 9

Divide both sides by 12:

x = 9/12

12x +1 = -10

Subtract 1 from both sides:

12x = -11

Divide both sides by 12:

x = -11/12

The answer would be (-11/12, 912)

8 0
3 years ago
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