Answer to this question please?

Mathematics

2 answers:

Goryan [66]3 years ago

5 0

I believe the correct answer is letter B: Nayaley's sales goal.

Ludmilka [50]3 years ago

5 0

B: <span>Nayaley's sales goal.</span>

You might be interested in

At the airport, the car rental store charges a $25.00 initial rental fee and $30.00 an hour to use the car. What is the total co

Assoli18 [71]

30.00x3=90.00$+25.00$=115.00$ so it has to be 115.00)

5 0

3 years ago

-12=5(6x+4)+7(x+6) is the question

Ilia_Sergeevich [38]

Answer:

x=-2

Step-by-step explanation:

-12=5(6x+4)+7(x+6)

30x+20+7x+42=-12

37x+62=-12

37x=-12-62

37x=-74

x= -2

I hope this will help you

3 0

4 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

4 years ago

I need help with this problem

Misha Larkins [42]

I think first 80 and second 90

4 0

3 years ago

[12÷(9-6)]+4×6 <br>please help

Pavel [41]

The answer is 28 ez.

8 0

3 years ago

Read 2 more answers