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tino4ka555 [31]
3 years ago
14

Answer to this question please?

Mathematics
2 answers:
Goryan [66]3 years ago
5 0
I believe the correct answer is letter B:  Nayaley's sales goal.
Ludmilka [50]3 years ago
5 0
B:  <span>Nayaley's sales goal.</span>
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It is predicted that the population of a particular state will double every 25 years. a) Determine the annual and monthly growth
Makovka662 [10]
B...

Hope this helps!
4 0
3 years ago
The product of a number and 7, decreased by the number is equal to 42. Find the number.
evablogger [386]

7
this is the answer, its pretty simple. I'm not sure the mathematical procedures but if you plug in 7 you get 49. Then all you got to do is subtract by 7, because the question states the number is the same. So basically,
7(7) - 7 = 42

8 0
3 years ago
Answer me please now
Anna35 [415]

Answer:

1. $8.

2. 48 counters.

Step-by-step explanation:

1. A pair of socks cost 20 - 2(6)

= $8.

2. let the number of counters in Box A and Box be be x.

Then the number of counters in Box B after the transfer is x + 1/2 x.

x + 1/2 x = 72

1.5 x = 72

x = 72 / 1.5

= 48.

4 0
3 years ago
Read 2 more answers
Pls help many thanks
salantis [7]

So, let's make these two values improper fractions so they're easier to work with. 4+\frac{1}{3}=\frac{12}{3}+\frac{1}{3}=\frac{13}{3} 3+\frac{1}{2}=\frac{6}{2}+\frac{1}{2}=\frac{7}{2}

So, to get the rate he grew in those months we have:

\frac{\frac{13}{3} \text{inches}}{\frac{7}{2}\text{months}} =\frac{26\text{inches}}{21\text{months}}

And to get the rate he grew in one month we have to divide both our numerator and our denominator by 21 to get:

\frac{\frac{26}{21} \text{inches}}{\text{month}}\approx \frac{1.24\text{inches}}{\text{month}} aka he grew 1.24 inches in a month.

7 0
3 years ago
Read 2 more answers
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
3 years ago
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