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kicyunya [14]
2 years ago
12

Find the absolute maximum and absolute minimum values, if any, of the function. (If an answer does not exist, enter DNE.)f(x) =

x2 − x − 5 on [0, 5]
Mathematics
1 answer:
lyudmila [28]2 years ago
7 0

Answer:

The absolute minimum value is "-\frac{21}{4}" and the absolute maximum value is "15".

Step-by-step explanation:

Given:

f(x)=x^2-x-5

on,

[0,5]

By differentiating it, we get

⇒ f'(x)=2x-1

Set f'(x)=0

then,

⇒ 2x-1=0

          2x=1

            x=\frac{1}{2} (Critical point)

When x=0,

⇒ f(x)=-5

When x=\frac{1}{2},

⇒ f(x)=-\frac{21}{4} (Absolute minimum)

When x=5

⇒ f(x)=15 (Absolute maximum)

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