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denis-greek [22]
3 years ago
9

The area of the rectangular flowerbed shown is 20.4 square meters. How many meters of edging are needed to go around the flowerb

ed? Explain
Mathematics
1 answer:
Temka [501]3 years ago
5 0
There are needed 24.7 meters to go around the flowerbed.
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Each month, Liz pays $35 to her phone company just to use the phone. Each text she sends costs her an additional $0.05. In March
Firdavs [7]
<h3><u>Answer:</u></h3><h3><u>752 & 617</u></h3><h3 /><h3><u>Explanation:</u></h3><h3><u>So if Liz pays $35 each month just to use the phone, we could subtract 35 from the total bill that month to get the the total cost she spent on text messages.</u></h3><h3 /><h3><u>March:$72.60-$35=$37.60</u></h3><h3><u>April: $65.85-$35=$30.85</u></h3><h3 /><h3><u>We can see that in March Liz spent $37.60 on texts in total and in April she spent $30.85 on texts in total. All we have to do is divide the amount of money she spent on texts( $37.60 & $30.85) by the cost of one text message($0.05) to get the amount of texts she sent that month.</u></h3><h3 /><h3><u>March: $37.60/$0.05=752</u></h3><h3><u>April: $30.85/$0.05=617</u></h3><h3 /><h3><u>Therefore, she sent 752 texts in March and 617 texts in April.</u></h3><h3 /><h3><u>~FrxziteTheLxoser~ I hoped I help you  :)</u></h3>

<u>If i helped you please give me brainIIlest!</u>

3 0
3 years ago
Will mark you as brainliest. If your good with polynomials.
kobusy [5.1K]
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)

14x^2-8+5x-6x^2+2x

group the x^2 (add 14x^2 to -6x^2)

8x^2-8+5x+2x

group the x's together (add 5x and 2x together)

8x^2+7x-8

Your answer will be d) 8x^2+7x-8



4 0
4 years ago
The diffrence between an integer p and (-5) is 1 find the value of p ​
Nastasia [14]

Solution:

<u>Note that:</u>

  • Given sentence: The difference between an integer p and (-5) is 1.

<u>Let's reread the sentence carefully.</u>

The difference between an integer p and (-5) is 1.

  • => p - (-5) = 1

<u>Change the sign.</u>

  • p - (-5) = 1
  • => p + 5 = 1

<u>Subtract 5 both sides:</u>

  • p + 5 = 1
  • => p + 5 - 5 = 1 - 5
  • => p = -4

4 0
3 years ago
The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units
nydimaria [60]

Answer:

  The volume of the prism is equal to the volume of the cylinder

Step-by-step explanation:

For each solid figure, the volume formula is ...

  V = Bh

where B is the cross-sectional area and h is the height. The problem statement tells us B and h have the same values for both figures. Hence their volumes are the same.

5 0
3 years ago
Maggie was doing research for her Ph.D. in physics when a 12 mg sample of radioactive material decayed to 3 mg in 26 minutes. De
netineya [11]

The general way to work this out is to solve the general expression for
the remaining quantity versus half-life, using logarithms.  But that's not
necessary with these numbers.

Look at the numbers:

-- 3 mg is  1/4  of  12 mg.

-- 1/4  is the product of  (1/2) x (1/2).

-- So the  3 mg is what's left of  12 mg after  2  half-lives.
The  26  minutes must be two half-lives.

-- The half-life of that substance is  26/2 = <em>13 minutes</em>.

Go Maggie !

3 0
3 years ago
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