Well, it depends on what he's doing. Is he walking, jogging, or running? If he walked at a normal pace for an hour he would burn 415calories.
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Hi there!
Since triangle RST is stated with the sides in order (R is connected to S, which is connected to T, which is then connected to R), the side between R and S is T.
Hope this helps!
Answer:
35 - 2.4(7-5)
= (35/1)-(24/10)(7-5)
= [(35×10)/(1×10)]-(24/10)(2)
= (350/10)-(24/10)(2)
= (350-24)/10(2)
= 326/10(2)
= 32.6(2)
= 65.2
Thank you.
BY GERALD GREAT.
