Answer:
37
Step-by-step explanation:
Use the given functions to set up and simplify
Answer:
Jaylen's conclusion is a valid conclusion because it is logical
Step-by-step explanation:
Jaylen's conclusion is a valid conclusion because it is logical. Regardless of not having all the necessary information needed to prove that the number of dogs is the sole main cause for an increase in cleaner usage she can still conclude this. Since dogs naturally bring in dirt from outside and make messes, and since Jaylene notices that families that are known to have more dogs are buying more floor cleaner then she can logically come to this conclusion.
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables 
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that 
We need to proof that 
by the definition of binomial random variable then we need to show that:
The deduction is based on the definition of independent random variables, we can do this:
And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor 
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that
Hey there :)
( 5y + 9 )( 6y - 1 )
We need to use FOIL to expand, that is
First Terms
Outer Terms
Inner Terms
Last Terms
First Outer Inner Last
( 5y )( 6y ) + ( 5y )( - 1 ) + 9 ( 6y ) + 9 ( - 1 )
30y² - 5y + 54y - 9
Combine, if any, the like-terms
30y² + 49y - 9
