This is the concept of algebra, let the width be x height=x-4 length=2x+10 the volume of the box is: volume=length*width*height =x(x-4)(2x+10) expanding the above we get: (x^2-4x)(2x+10) =x^2(2x+10)-4x(2x+10) =2x^3+2x^2-40x=264 solving the above we get real solution will be x=6 thus we conclude that the width is x=6 inches length=2*6+10=22 inches height=x-4=6-4=2 inches thus the dimension will be: width=6 inches, length=22 inches, height=2 inches
