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3 years ago

How are 2^-3 and 2^3 are related

Mathematics

2 answers:

olchik [2.2K]3 years ago

8 0

They are both 2^3 away from 0 if thats wht ur asking.

solong [7]3 years ago

6 0

Answer:

2⁻³ and 2³ are inverses of each other. That means they multiply to 1.

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Find the area and the circumference of a circle with the radius 3 ft.Use 3.14 for pi

Lilit [14]

ANSWER

• Circumference: 18.84 ft

• Area: 28.26 ft²

EXPLANATION

The circumference of a circle of radius r is,

$C=2\pi r$

In this case, the radius is r = 3 ft and we have to use 3.14 for π,

$C=2\cdot3.14\cdot3ft=18.84ft$

Hence, the circumference of this circle is 18.84 feet.

The area of a circle of radius r is,

$A=\pi r^2$

In this case, r = 3 ft and π = 3.14,

$A=3.14\cdot3^2ft^2=28.26ft^2$

Hence, the area of this circle is 28.26 square feet.

6 0

1 year ago

WILL MARK AS BRAINLIEST!!! Write a numerical expression for the phrase, then simplify it. The product of 13 and the difference b

hjlf

" · " - product

" - " - difference

13 · (8 - (-10)) = 13 · (8 + 10) = 13 · 18 = 234

5 0

3 years ago

Since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year. Predict th

BaLLatris [955]

Answer:

20,158 cases

Step-by-step explanation:

Let $t=0$ represent year 2010.

We have been given that since 2010, when 102390 Cases were reported, each year the number of new flu cases decrease to 85% of the prior year.

Since the flu cases decrease to 85% of the prior year, so the flu cases for every next year will be 85% of last year and decay rate is 15%.

We can represent this information in an exponential decay function as:

$F(t)=102,390(1-0.15)^t$

$F(t)=102,390(0.85)^t$

To find number of cases in 2020, we will substitute $t=10$ in our decay function as:

$F(10)=102,390(0.85)^{10}$

$F(10)=102,390(0.1968744043407227)$

$F(10)=20,157.970260446597\approx 20,158$

Therefore, 20,158 cases will be reported in 2020.

3 0

2 years ago

Suppose a normal distribution has a mean of 222 and a standard deviation of 16. What is the probability that a data value is bet

valentina_108 [34]

Mean of the distribution = u = 222
Standard Deviation = s = 16

We have to find the probability that a value lies between 190 and 230.

First we need to convert these data values to z score.

$z= \frac{x-u}{s}$

For x = 190,
$z= \frac{190-222}{16}=-2$

For x = 230
$z= \frac{230-222}{16}=0.5$

So, we have to find the percentage of values lying between z score of -2 and 0.5

P( -2 < z < 0.5) = P(0.5) - P(-2)

From standard z table, we can find and use these values.

P(-2 < x < 0.5 ) = 0.6915 - 0.0228 = 0.6687

Thus, there is 0.6887 probability that the data value will lie between 190 and 230 for the given distribution.

5 0

3 years ago

There are no solutions to the system of inequalities shown belov

Aleks04 [339]

Answer:

B. False

step by step explanation

3 0

2 years ago