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Aleks [24]
3 years ago
15

hi, i hope everyone is taking care, staying safe, and always smiling. could you help me? it is maths, brainliest will be given

Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

210 cm³

Step-by-step explanation:

The area of the triangular side is base*half height, which is 7*3=21.

To get the volume, multiply by the depth: 21*10 = 210 cm³

Kaylis [27]3 years ago
7 0

Answer:

hey !

the answer to your question is 210cm3

Step-by-step explanation:

this is because you do 7cm times 6cm times 10cm

this would equal 420cm3

but dont forget you have to divide it by 2 because it is a triangluar prism

so the answer would be 210cm3

hope this helps

pls put brainliest

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Rewrite the equation <br> x + y + 3 = -2x + 4y + 18 <br> into general form
dolphi86 [110]

Answer:

x-y=5 just solve it to get the answer

5 0
2 years ago
4. The table below shows the cost of pencils at the local discount store. Cost of Pencils Number of Total Cost Pencils 10 $1.25
fomenos

Answer:

1.25 / 10 = 0.125

0.125 is about 0.13

13 cents or $0.13

4 0
2 years ago
The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th
finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0
3 years ago
Find the slope I need help plz
ira [324]
I dont know sorry i am also bad in math

5 0
3 years ago
What value(s) of x will make each equation below true
Dahasolnce [82]

We need to solve for x. Let's try problem b:

2x-6=3x+1-x-7

Let us first combine line terms. 3x and -x as well as 1 and -7 can be combined. Let's do that:

2x-6=2x-6

Since this is true, your answer would be:

All real numbers

------------------------------------------------------------------

Let's solve for problem c:

3x+1=43

Let's isolate x, so subtract 1 from both sides:

3x=42

Since x can't have a coefficient, divide both sides by 3:

\frac{3x}{3}=\frac{42}{3}

x=14

So, only the value of 14 would make this equation true.

------------------------------------------------------------------

Let's try problem d:

4x-1=4x+7

Let's get our whole numbers on the right side. Add 1 to both sides:

4x=4x+8

Subtract 4x from the right side on both sides:

0=8

Since this is not true, your answer would be:

No solution

7 0
3 years ago
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