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Dominik [7]
3 years ago
15

Y is between points p and b. pt= 15 and tb = 10. what is pb

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
PT = 15, and TB = 10 

Take the 15 from PT, and add the 10 from TB. Which equals 25. 

PB = 25 

So, 25 is your answer. 

Hope this helps! ☺
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Help me plz I'm stuck
Lelechka [254]
The answer to one would be 25534
3 0
3 years ago
Dylan read his book for 2 2/3 hours and Faith read her's for 1 1/5.How much longer did did Dylan read then Faith?
Damm [24]

Answer:

1 7/15

Step-by-step explanation:

2-1=1

then you make 2/3 and 1/5 have the same denominator -

5*3=15

?/15                       ?/15

multiply 2 by 5 which is 10, so 10/15

then multiply 1 by 3 which is 3/15

subtract 3/15 from 10/15 which is 7/15

4 0
3 years ago
Can i get help please i don't know this
scoundrel [369]
I think it means you have to find the area of both shapes and then compare them to see if Liam is correct if he is not correct say why. Hope this helps :)
3 0
3 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
Which equation represents the line that passes through the points (6,-3) and (-4,-9)?
Citrus2011 [14]
I will give in y=mx+b and ax+by=c form

using point slope form
y-y1=m(x-x1)
where the slope is m and a point on that line is (x1,y1)

slope between 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x1-x1)

given
(6,-3) and (-4,-9)
slope=(-9-(-3))/(-4-6)=(-9+3)/(-10)=-6/-10=3/5
a point is (6,-3)

y-(-3)=3/5(x-6)
y+3=3/5(x-6)
y+3=3/5x-18/5
y=3/5x-33/5
-3/5x+y=-33/5
3x-5y=33


equation is
y=3/5x-33 or
3x-5y=33 or
y+3=3/5(x-6) or
y+9=3/5(x+4)
7 0
3 years ago
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