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Vlad1618 [11]
4 years ago
9

-5x-6(-6+3x)=105 what is the answer

Mathematics
1 answer:
lyudmila [28]4 years ago
3 0

Answer:

x = -3

Step-by-step explanation:

expand -23x + 36 = 105

subtract 36 from both sides -23x +36 -36 = 105 - 36

Simplify -23x = 69

Divid both sides by -23: -23x / - 23 = 69 / -23

x = -3

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Answer:

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Step-by-step explanation:

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3 years ago
The sum of two numbers is 39 and the difference is 3. What are the numbers?
frosja888 [35]

Answer: 21 & 18

Step-by-step explanation:

Sum of two numbers is 39

Difference is 3

Let the numbers be x & y

X+y=39........equation 1

X-y=3...........equation 2

X=3+y............equation 3

Substitute equation 3 into equation 1

(3+y)+y=39

3+y+y=39

3+2y=39

2y=39-3

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Y=36/2

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Substitute for y in equation 2

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8 0
4 years ago
If cosx=1/12 and sinx>0 find tan2x
Liono4ka [1.6K]
cosx=\frac{1}{12}\\\\sin^2x+cos^2x=1\\\\sin^2x+\left(\frac{1}{12}\right)^2=1\\\\sin^2x+\frac{1}{144}=1\\\\sin^2x=1-\frac{1}{144}\\\\sin^2x=\frac{144}{144}-\frac{1}{144}\\\\sin^2x=\frac{143}{144}\\\\sinx=\sqrt\frac{143}{144}\\\\sinx=\frac{\sqrt{143}}{12}


tan2x=\frac{sin2x}{cos2x}\\\\sin2x=2sinxcosx;\ cos2x=cos^2x-sin^2x\\\\sin2x=2\cdot\frac{\sqrt{143}}{12}\cdot\frac{1}{12}=\frac{2\sqrt{143}}{144}\\\\cos2x=\left(\frac{1}{12}\right)^2-\left(\frac{\sqrt{143}}{12}\right)^2=\frac{1}{144}-\frac{143}{144}=-\frac{142}{144}\\\\tan2x=\frac{2\sqrt{143}}{144}:\left(-\frac{142}{144}\right)=-\frac{2\sqrt{143}}{144}\cdot\frac{144}{142}=-\frac{\sqrt{143}}{71}
3 0
3 years ago
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arlik [135]
Remember that the circle formula is (x – h)2 + (y – k)2 = r<span>2 where h and k represents the center of the circle. We determine as follows:

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</span><span> (h,k) = 5,-7 QUADRANT 4</span>

<span>C.(x - 9)2 + (y + 9)2 = 16
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5 0
3 years ago
After going shopping we had only 10% of our money left. We spent $180 how much money did we have at first
aivan3 [116]

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