Answer:
0.26 minutes
Step-by-step explanation:
So if you want to solve this, you need to make all the units the same first. What you first need to work on is the rate, since what it is asking is minutes given distance in feet.
We know that there are:
5280 ft in a mile
60 minutes in an hour
We then convert the rate knowing this:

In short, the car is traveling 3,828 ft every minute.
To determine how many minutes it will take for the car to travel just remember that:

Now we plug in what we know and solve what we don't know:

Answer:
b / (b - 8)
Step-by-step explanation:
Given that :
Litres of water held by bucket = b
Jar holds 8 litres fewer than bucket; hence, litres held by jar = b - 8
The number of times bucket can hold than jar is :
Litres held by bucket / litres held by jar
b / (b - 8)
Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles