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Stels [109]
3 years ago
9

What is the largest prime factor of 34

Mathematics
2 answers:
Sophie [7]3 years ago
6 0
34|2
17|17
1

It's 17.

................
AnnyKZ [126]3 years ago
3 0
Seventeen is the largest prim factor of thirtyfour
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Solve equation for y: -4x+8y=24
Nesterboy [21]
-4x +8y = 24

8y = 24+ 4x
y = 24/8 + 4x/8
y = 3+ x/2

Hope it helps!
#MissionExam001
4 0
3 years ago
Sawyer is ordering sets of guitar strings and bags of picks for his guitar. A new set of strings costs $12 and a new bag of pick
quester [9]

Answer: The equation is 16g+6 ,lmk if you need the answer :)

Step-by-step explanation:

4 0
3 years ago
What is the ratio of circles to total shapes
Soloha48 [4]
Hm i think it might be 2:8?
6 0
2 years ago
The U.S. Department of Transportation provides the number of miles that residents of the75 largest metropolitan areas travel per
Leya [2.2K]

Answer:

a. The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88

b. The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

Step-by-step explanation:

a. According to the given data we have the following:

Buffalo residents mean=22.5

Standard deviation=8.4

n=50

Boston residents mean=18.6

Standard deviation=7.4

n=40

Hence, the point estimate is the difference of the means=22.5-18.6=3.9

The standard error=√((s1∧2/n1)+((s2∧2/n2))=√((8.4∧2/50)+(7.4∧2/40))=1.67

Therefore, the difference of miles=n1+n2-2=50+40-2=88

The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88.

b. The critical value of t at 95% confidence level and DoF=88 is 1.987

The interval:(x1-x2)+ (critical value* std error)

=3.9-(1.987*1.67),3.9+(1.987*1.67)

Difference between mean=(0.58171,7.21829)

The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

8 0
2 years ago
Suppose you invest $7500 at an annual interest rate of 4.2% compounded continuously. How much will you have in the account after
tatyana61 [14]
<span>Interest=principle x rate x time (in years)
so putting values so
Interest=7500 (.042)(2)
 so
 Interest=630 7500+630=8130
 Interest=500 (.071)(4)
Interest=142 500+142=64
hope it helps</span>
6 0
3 years ago
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