Answer:
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Explanation:
Step 1: Data given
Ag(s) + H2S(g) → Ag,S(s) + H2(g)
Ag has and oxidation number of +1
S has an oxidation number of -2
H has an oxidation number of +1
Step 2: The balanced equation
Ag+ + 2H+ + S^2- →
The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.
2 H- atoms will appear as H2.
The balanced equation is:
2Ag+ + 2H+ +S^2- → Ag2S + H2
2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)
Answer:
The answer to your question is 100.8 g
Explanation:
Data
mass of Barium chloride = 90 g
mass of Barium sulfate = ?
Balanced chemical reaction
BaCl₂ + H₂SO₄ ⇒ BaSO₄ + 2HCl
Process
1.- Calculate the molar mass of BaCl₂ and BaSO₄
BaCl₂ = 137.3 + (2 x 35.5) = 208.3g
BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g
2.- Use proportions to find the mass of BaSO₄
208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄
90 g of BaCl₂ --------------------- x
x = (90 x 233.3) / 208.3
x = 20997/ 208.3
x = 100.8 g
3.- Conclusion
There will be produced 100.8 g of BaSO₄
Answer:
15.2
Explanation:
the chemical reaction in chemistry libretto texts.
