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Liono4ka [1.6K]
3 years ago
8

If 14.5kj of heat were added to 485g of liquid water, how much would its temp increase

Chemistry
1 answer:
OlgaM077 [116]3 years ago
6 0
<span>7.15 degrees C The specific heat capacity of water is 4.1813 J/(g*K). So we have 3 values with the units kJ, g and J/(g*K). We can trivially convert from kJ to J by multiplying by 1000. And we want to get a result with the unit K (degrees Kelvin). So let's do it. First, let's cancel out the g unit by multiplying. 4.1813 J/(g*K) * 485 g = 2027.9305 J/K Now we can cancel out the J unit by dividing. But if we divide by the energy, we'll be left with the reciprocal of K, not K. So instead divide by the J/K unit. So 14500 J / 2027.9305 J/K = 7.150146418 K Rounding to 3 significant figures gives us 7.15 K. And since degrees C and degrees K are the same size, the temperature will increase by 7.15 degrees C</span>
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A description of a material that scatters light that passes through it
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Answer:

triangular prism

Explanation:

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What energy is required to move from Ca+ to Ca2+ + e−?
nataly862011 [7]

Second Ionization energy is required to move from  Ca⁺ to Ca²⁺ + e⁻. Hence, option D is correct.

<h3>What is first ionization energy?</h3>

First ionization energy: The energy needed to remove the outermost, or highest energy, an electron from a neutral atom in the gas phase.

An element's second ionization energy is the energy required to remove the outermost, or least bound, an electron from a 1+ ion of the element. Because positive charge binds electrons more strongly, the second ionization energy of an element is always higher than the first.

Let us write the reaction equation properly:

                 Ca⁺ → Ca²⁺ + e⁻

In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.

Different atoms bind their valence electrons with different amounts of energy. We must supply enough energy to remove the most loosely held electrons in an atom. This amount of energy required is called ionization energy.

The first ionization energy removes the outermost electron and makes the atom to become an ion.

Hence, option D is correct.

Learn more about the ionization energy here:

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4 0
2 years ago
How many kilojoules are required to convert 115.0 g of ice at 0.0 ∘c to liquid water at 32 ∘c? the heat of fusion of water is 33
Ivanshal [37]
The answer is 53.8 kJ.
Solution:There are two major steps in converting ice to liquid water. It begins with a phase change when ice melts at 0.0°C, and then a temperature change when the liquid water rises in temperature from zero to 32°C.
The amount of heat involved with the phase change melting is given by
     q = (mass of water) (ΔHfus)
        = (115.0 g)(334 J/g) 
        = 38410 J = 38.41 kJ
The amount of heat involved with temperature change is 
     q = mcΔT
        = (115.0g)(4.184J/g°C)(32°C - 0.0°C)
        = 15397.12 J = 15.39712 kJ
Summing up the two values gives the total heat required to convert ice to liquid water:
     q = 38.41 kJ + 15.39712 kJ= 53.8 kJ
3 0
3 years ago
What is the optimum pH to separate a mixture of lysine, arginine, and cysteine using electrophoresis
belka [17]

Answer:

9.5

Explanation:

Electrophoresis is a separation technique which involves the passage and the use of electric current in separating amino acid mixtures. The positively charged protein moves to the negative electrode while the negatively charged protein moves to the positive electrode which is in accordance to the law of attraction.

Proteins however perform optimally at the right temperature and pH. Studies shows that the optimum pH to separate a mixture of lysine, arginine, and cysteine using the electrophoresis method of separation is around 9.5

4 0
4 years ago
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