Question

If 14.5kj of heat were added to 485g of liquid water, how much would its temp increase

Answer 1

7.15 degrees C The specific heat capacity of water is 4.1813 J/(g*K). So we have 3 values with the units kJ, g and J/(g*K). We can trivially convert from kJ to J by multiplying by 1000. And we want to get a result with the unit K (degrees Kelvin). So let's do it. First, let's cancel out the g unit by multiplying. 4.1813 J/(g*K) * 485 g = 2027.9305 J/K Now we can cancel out the J unit by dividing. But if we divide by the energy, we'll be left with the reciprocal of K, not K. So instead divide by the J/K unit. So 14500 J / 2027.9305 J/K = 7.150146418 K Rounding to 3 significant figures gives us 7.15 K. And since degrees C and degrees K are the same size, the temperature will increase by 7.15 degrees C