Answer:
15.2 g H2
Explanation:
2H2O -> 2H2 + O2
9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2
The molar concentration of the nitric acid solution was 0.6666 mol/L.
<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O
<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)
= 33.33 mmol KOH
<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)
= 33.33 mmol HNO_3
<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL
= 0.6666 mol/L
Answer is: Kp = 66,586.
Chemical reaction: PCl₃(g) + Cl₂(g) ⇔ PCl₅(g).
Kp - equilibrium constants expressed in terms of partial pressures of gases.
Kp = p(PCl₅) ÷ p(PCl₃) · p(Cl₂). p-partial pressure.
Kp = 1,67 atm ÷ 0,132 atm · 0,190 atm
Kp = 66, 586 1/atm. Favors product.
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