Question

We want to select a committee of five members from a group of six women and six men. the order of selection is irrelevant. how many committees can we make with fewer men than women? suggestion: there could be three women and two men, four women and one man, or five women.

Answer 1

3 women, 2 men
6C3 * 6C2 = 300

4 women, 1 man
6C4 * 6C1 = 90

5 women, 0 men
6C5 = 6

"or" means to add
300 + 90 + 6 = 396 different committees